Abi and Ivory have some shortbreads each. If Abi gives Ivory 23 shortbreads, Abi will have ¹₂ as many shortbreads as Ivory. If Abi gives Ivory 10 shortbreads, they will have an equal number of shortbreads. How many shortbreads does Ivory have at first?

	Case 1		Case 2
	Abi	Ivory	Abi	Ivory
Before	1 u + 23	2 u - 23	1.5 u + 10	1.5 u - 10
Change	- 23	+ 23	- 10	+ 10
After	1 u	2 u	1.5 u	1.5 u

Total number of shortbreads that Abi and Ivory have
= 1 u + 2 u
= 3 u 

Number of shortbreads that Abi and Ivory each has in the end is the same.

Number of shortbreads that Abi and Ivory each has in the end in Case 2
= 3 u ÷ 2
= 1.5 u

Number of shortbreads that Abi had at first is the same in Case 1 and Case 2.

1.5 u + 10 = 1 u + 23
1.5 u - 1 u = 23 - 10
0.5 u = 13

1 u = 13 ÷ 0.5 = 26

Number of shortbreads that Ivory has
= 2 u - 23
= 2 x 26 - 23
= 52 - 23
= 29

Answer(s): 29