Yoko and Wendy have some biscuits each. If Yoko gives Wendy 34 biscuits, Yoko will have ⁶₇ as many biscuits as Wendy. If Yoko gives Wendy 7 biscuits, they will have an equal number of biscuits. How many biscuits does Wendy have at first?

	Case 1		Case 2
	Yoko	Wendy	Yoko	Wendy
Before	6 u + 34	7 u - 34	6.5 u + 7	6.5 u - 7
Change	- 34	+ 34	- 7	+ 7
After	6 u	7 u	6.5 u	6.5 u

Total number of biscuits that Yoko and Wendy have
= 6 u + 7 u
= 13 u 

Number of biscuits that Yoko and Wendy each has in the end is the same.

Number of biscuits that Yoko and Wendy each has in the end in Case 2
= 13 u ÷ 2
= 6.5 u

Number of biscuits that Yoko had at first is the same in Case 1 and Case 2.

6.5 u + 7 = 6 u + 34
6.5 u - 6 u = 34 - 7
0.5 u = 27

1 u = 27 ÷ 0.5 = 54

Number of biscuits that Wendy has
= 7 u - 34
= 7 x 54 - 34
= 378 - 34
= 344

Answer(s): 344