Xandra and Fanny have some shortbreads each. If Xandra gives Fanny 34 shortbreads, Xandra will have
67 as many shortbreads as Fanny. If Xandra gives Fanny 5 shortbreads, they will have an equal number of shortbreads. How many shortbreads does Fanny have at first?
|
Case 1 |
Case 2 |
|
Xandra |
Fanny |
Xandra |
Fanny |
Before |
6 u + 34 |
7 u - 34 |
6.5 u + 5 |
6.5 u - 5 |
Change |
- 34 |
+ 34 |
- 5 |
+ 5 |
After |
6 u |
7 u |
6.5 u |
6.5 u |
Total number of shortbreads that Xandra and Fanny have
= 6 u + 7 u
= 13 u
Number of shortbreads that Xandra and Fanny each has in the end is the same.
Number of shortbreads that Xandra and Fanny each has in the end in Case 2
= 13 u ÷ 2
= 6.5 u
Number of shortbreads that Xandra had at first is the same in Case 1 and Case 2.
6.5 u + 5 = 6 u + 34
6.5 u - 6 u = 34 - 5
0.5 u = 29
1 u = 29 ÷ 0.5 = 58
Number of shortbreads that Fanny has
= 7 u - 34
= 7 x 58 - 34
= 406 - 34
= 372
Answer(s): 372