Yoko and Irene have some scones each. If Yoko gives Irene 29 scones, Yoko will have ⁶₇ as many scones as Irene. If Yoko gives Irene 3 scones, they will have an equal number of scones. How many scones does Irene have at first?

	Case 1		Case 2
	Yoko	Irene	Yoko	Irene
Before	6 u + 29	7 u - 29	6.5 u + 3	6.5 u - 3
Change	- 29	+ 29	- 3	+ 3
After	6 u	7 u	6.5 u	6.5 u

Total number of scones that Yoko and Irene have
= 6 u + 7 u
= 13 u 

Number of scones that Yoko and Irene each has in the end is the same.

Number of scones that Yoko and Irene each has in the end in Case 2
= 13 u ÷ 2
= 6.5 u

Number of scones that Yoko had at first is the same in Case 1 and Case 2.

6.5 u + 3 = 6 u + 29
6.5 u - 6 u = 29 - 3
0.5 u = 26

1 u = 26 ÷ 0.5 = 52

Number of scones that Irene has
= 7 u - 29
= 7 x 52 - 29
= 364 - 29
= 335

Answer(s): 335