Emily and Barbara have some croissants each. If Emily gives Barbara 23 croissants, Emily will have
34 as many croissants as Barbara. If Emily gives Barbara 17 croissants, they will have an equal number of croissants. How many croissants does Emily have at first?
|
Case 1 |
Case 2 |
|
Emily |
Barbara |
Emily |
Barbara |
Before |
3 u + 23 |
4 u - 23 |
3.5 u + 17 |
3.5 u - 17 |
Change |
- 23 |
+ 23 |
- 17 |
+ 17 |
After |
3 u |
4 u |
3.5 u |
3.5 u |
Total number of croissants that Emily and Barbara have
= 3 u + 4 u
= 7 u
Number of croissants that Emily and Barbara each has in the end is the same.
Number of croissants that Emily and Barbara each has in the end in Case 2
= 7 u ÷ 2
= 3.5 u
Number of croissants that Emily had at first is the same in Case 1 and Case 2.
3.5 u + 17 = 3 u + 23
3.5 u - 3 u = 23 - 17
0.5 u = 6
1 u = 6 ÷ 0.5 = 12
Number of croissants that Emily has
= 3 u + 23
= 3 x 12 + 23
= 36 + 23
= 59
Answer(s): 59