Emma and Zoe have some croissants each. If Emma gives Zoe 11 croissants, Emma will have ¹₂ as many croissants as Zoe. If Emma gives Zoe 8 croissants, they will have an equal number of croissants. How many croissants does Emma have at first?

	Case 1		Case 2
	Emma	Zoe	Emma	Zoe
Before	1 u + 11	2 u - 11	1.5 u + 8	1.5 u - 8
Change	- 11	+ 11	- 8	+ 8
After	1 u	2 u	1.5 u	1.5 u

Total number of croissants that Emma and Zoe have
= 1 u + 2 u
= 3 u 

Number of croissants that Emma and Zoe each has in the end is the same.

Number of croissants that Emma and Zoe each has in the end in Case 2
= 3 u ÷ 2
= 1.5 u

Number of croissants that Emma had at first is the same in Case 1 and Case 2.

1.5 u + 8 = 1 u + 11
1.5 u - 1 u = 11 - 8
0.5 u = 3

1 u = 3 ÷ 0.5 = 6

Number of croissants that Emma has
= 1 u + 11
= 1 x 6 + 11
= 6 + 11
= 17

Answer(s): 17