Betty and Xylia have some wafers each. If Betty gives Xylia 39 wafers, Betty will have ⁴₅ as many wafers as Xylia. If Betty gives Xylia 10 wafers, they will have an equal number of wafers. How many wafers does Xylia have at first?

	Case 1		Case 2
	Betty	Xylia	Betty	Xylia
Before	4 u + 39	5 u - 39	4.5 u + 10	4.5 u - 10
Change	- 39	+ 39	- 10	+ 10
After	4 u	5 u	4.5 u	4.5 u

Total number of wafers that Betty and Xylia have
= 4 u + 5 u
= 9 u 

Number of wafers that Betty and Xylia each has in the end is the same.

Number of wafers that Betty and Xylia each has in the end in Case 2
= 9 u ÷ 2
= 4.5 u

Number of wafers that Betty had at first is the same in Case 1 and Case 2.

4.5 u + 10 = 4 u + 39
4.5 u - 4 u = 39 - 10
0.5 u = 29

1 u = 29 ÷ 0.5 = 58

Number of wafers that Xylia has
= 5 u - 39
= 5 x 58 - 39
= 290 - 39
= 251

Answer(s): 251