Jaslyn and Tina have some croissants each. If Jaslyn gives Tina 12 croissants, Jaslyn will have ⁴₇ as many croissants as Tina. If Jaslyn gives Tina 2 croissants, they will have an equal number of croissants. How many croissants does Tina have at first?

	Case 1		Case 2
	Jaslyn	Tina	Jaslyn	Tina
Before	4 u + 12	7 u - 12	5.5 u + 2	5.5 u - 2
Change	- 12	+ 12	- 2	+ 2
After	4 u	7 u	5.5 u	5.5 u

Total number of croissants that Jaslyn and Tina have
= 4 u + 7 u
= 11 u 

Number of croissants that Jaslyn and Tina each has in the end is the same.

Number of croissants that Jaslyn and Tina each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u

Number of croissants that Jaslyn had at first is the same in Case 1 and Case 2.

5.5 u + 2 = 4 u + 12
5.5 u - 4 u = 12 - 2
0.5 u = 10

1 u = 10 ÷ 0.5 = 20

Number of croissants that Tina has
= 7 u - 12
= 7 x 20 - 12
= 140 - 12
= 128

Answer(s): 128