Vanessa and Xylia have some cupcakes each. If Vanessa gives Xylia 19 cupcakes, Vanessa will have
58 as many cupcakes as Xylia. If Vanessa gives Xylia 11 cupcakes, they will have an equal number of cupcakes. How many cupcakes does Vanessa have at first?
|
Case 1 |
Case 2 |
|
Vanessa |
Xylia |
Vanessa |
Xylia |
Before |
5 u + 19 |
8 u - 19 |
6.5 u + 11 |
6.5 u - 11 |
Change |
- 19 |
+ 19 |
- 11 |
+ 11 |
After |
5 u |
8 u |
6.5 u |
6.5 u |
Total number of cupcakes that Vanessa and Xylia have
= 5 u + 8 u
= 13 u
Number of cupcakes that Vanessa and Xylia each has in the end is the same.
Number of cupcakes that Vanessa and Xylia each has in the end in Case 2
= 13 u ÷ 2
= 6.5 u
Number of cupcakes that Vanessa had at first is the same in Case 1 and Case 2.
6.5 u + 11 = 5 u + 19
6.5 u - 5 u = 19 - 11
0.5 u = 8
1 u = 8 ÷ 0.5 = 16
Number of cupcakes that Vanessa has
= 5 u + 19
= 5 x 16 + 19
= 80 + 19
= 99
Answer(s): 99