Elyse and Rachel have some tarts each. If Elyse gives Rachel 14 tarts, Elyse will have
29 as many tarts as Rachel. If Elyse gives Rachel 7 tarts, they will have an equal number of tarts. How many tarts does Elyse have at first?
|
Case 1 |
Case 2 |
|
Elyse |
Rachel |
Elyse |
Rachel |
Before |
2 u + 14 |
9 u - 14 |
5.5 u + 7 |
5.5 u - 7 |
Change |
- 14 |
+ 14 |
- 7 |
+ 7 |
After |
2 u |
9 u |
5.5 u |
5.5 u |
Total number of tarts that Elyse and Rachel have
= 2 u + 9 u
= 11 u
Number of tarts that Elyse and Rachel each has in the end is the same.
Number of tarts that Elyse and Rachel each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u
Number of tarts that Elyse had at first is the same in Case 1 and Case 2.
5.5 u + 7 = 2 u + 14
5.5 u - 2 u = 14 - 7
0.5 u = 7
1 u = 7 ÷ 0.5 = 14
Number of tarts that Elyse has
= 2 u + 14
= 2 x 14 + 14
= 28 + 14
= 42
Answer(s): 42