Anna and Pamela have some wafers each. If Anna gives Pamela 6 wafers, Anna will have
89 as many wafers as Pamela. If Anna gives Pamela 3 wafers, they will have an equal number of wafers. How many wafers does Anna have at first?
| |
Case 1 |
Case 2 |
| |
Anna |
Pamela |
Anna |
Pamela |
| Before |
8 u + 6 |
9 u - 6 |
8.5 u + 3 |
8.5 u - 3 |
| Change |
- 6 |
+ 6 |
- 3 |
+ 3 |
| After |
8 u |
9 u |
8.5 u |
8.5 u |
Total number of wafers that Anna and Pamela have
= 8 u + 9 u
= 17 u
Number of wafers that Anna and Pamela each has in the end is the same.
Number of wafers that Anna and Pamela each has in the end in Case 2
= 17 u ÷ 2
= 8.5 u
Number of wafers that Anna had at first is the same in Case 1 and Case 2.
8.5 u + 3 = 8 u + 6
8.5 u - 8 u = 6 - 3
0.5 u = 3
1 u = 3 ÷ 0.5 = 6
Number of wafers that Anna has
= 8 u + 6
= 8 x 6 + 6
= 48 + 6
= 54
Answer(s): 54
