Anna and Olivia have some croissants each. If Anna gives Olivia 22 croissants, Anna will have
23 as many croissants as Olivia. If Anna gives Olivia 19 croissants, they will have an equal number of croissants. How many croissants does Anna have at first?
|
Case 1 |
Case 2 |
|
Anna |
Olivia |
Anna |
Olivia |
Before |
2 u + 22 |
3 u - 22 |
2.5 u + 19 |
2.5 u - 19 |
Change |
- 22 |
+ 22 |
- 19 |
+ 19 |
After |
2 u |
3 u |
2.5 u |
2.5 u |
Total number of croissants that Anna and Olivia have
= 2 u + 3 u
= 5 u
Number of croissants that Anna and Olivia each has in the end is the same.
Number of croissants that Anna and Olivia each has in the end in Case 2
= 5 u ÷ 2
= 2.5 u
Number of croissants that Anna had at first is the same in Case 1 and Case 2.
2.5 u + 19 = 2 u + 22
2.5 u - 2 u = 22 - 19
0.5 u = 3
1 u = 3 ÷ 0.5 = 6
Number of croissants that Anna has
= 2 u + 22
= 2 x 6 + 22
= 12 + 22
= 34
Answer(s): 34