Roshel and Lucy have some wafers each. If Roshel gives Lucy 18 wafers, Roshel will have
47 as many wafers as Lucy. If Roshel gives Lucy 7 wafers, they will have an equal number of wafers. How many wafers does Lucy have at first?
|
Case 1 |
Case 2 |
|
Roshel |
Lucy |
Roshel |
Lucy |
Before |
4 u + 18 |
7 u - 18 |
5.5 u + 7 |
5.5 u - 7 |
Change |
- 18 |
+ 18 |
- 7 |
+ 7 |
After |
4 u |
7 u |
5.5 u |
5.5 u |
Total number of wafers that Roshel and Lucy have
= 4 u + 7 u
= 11 u
Number of wafers that Roshel and Lucy each has in the end is the same.
Number of wafers that Roshel and Lucy each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u
Number of wafers that Roshel had at first is the same in Case 1 and Case 2.
5.5 u + 7 = 4 u + 18
5.5 u - 4 u = 18 - 7
0.5 u = 11
1 u = 11 ÷ 0.5 = 22
Number of wafers that Lucy has
= 7 u - 18
= 7 x 22 - 18
= 154 - 18
= 136
Answer(s): 136