Marion and Betty have some puffs each. If Marion gives Betty 20 puffs, Marion will have
29 as many puffs as Betty. If Marion gives Betty 14 puffs, they will have an equal number of puffs. How many puffs does Marion have at first?
|
Case 1 |
Case 2 |
|
Marion |
Betty |
Marion |
Betty |
Before |
2 u + 20 |
9 u - 20 |
5.5 u + 14 |
5.5 u - 14 |
Change |
- 20 |
+ 20 |
- 14 |
+ 14 |
After |
2 u |
9 u |
5.5 u |
5.5 u |
Total number of puffs that Marion and Betty have
= 2 u + 9 u
= 11 u
Number of puffs that Marion and Betty each has in the end is the same.
Number of puffs that Marion and Betty each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u
Number of puffs that Marion had at first is the same in Case 1 and Case 2.
5.5 u + 14 = 2 u + 20
5.5 u - 2 u = 20 - 14
0.5 u = 6
1 u = 6 ÷ 0.5 = 12
Number of puffs that Marion has
= 2 u + 20
= 2 x 12 + 20
= 24 + 20
= 44
Answer(s): 44