Yoko and Betty have some croissants each. If Yoko gives Betty 22 croissants, Yoko will have ¹₆ as many croissants as Betty. If Yoko gives Betty 13 croissants, they will have an equal number of croissants. How many croissants does Yoko have at first?

	Case 1		Case 2
	Yoko	Betty	Yoko	Betty
Before	1 u + 22	6 u - 22	3.5 u + 13	3.5 u - 13
Change	- 22	+ 22	- 13	+ 13
After	1 u	6 u	3.5 u	3.5 u

Total number of croissants that Yoko and Betty have
= 1 u + 6 u
= 7 u 

Number of croissants that Yoko and Betty each has in the end is the same.

Number of croissants that Yoko and Betty each has in the end in Case 2
= 7 u ÷ 2
= 3.5 u

Number of croissants that Yoko had at first is the same in Case 1 and Case 2.

3.5 u + 13 = 1 u + 22
3.5 u - 1 u = 22 - 13
0.5 u = 9

1 u = 9 ÷ 0.5 = 18

Number of croissants that Yoko has
= 1 u + 22
= 1 x 18 + 22
= 18 + 22
= 40

Answer(s): 40