A bookshop sells pens in packs of 2 and 5. At first, there were 6 times as many packs of 2 as packs of 5. After selling half of the packs of 2 and some packs of 5, Mr Heng packs 14 additional packs of 5. How many packs of 2 are sold if there are 6 times as many packs of 2 as packs of 5 and there is a total of 136 unsold pens?
| |
Packs of 2 |
Packs of 5 |
Comparing the number
of packs at first |
6x2 =
12 u |
1x2 =
2 u |
| Before |
2x6 =
12 u |
|
| Change 1 |
- 1x6 =
- 6 u |
- ? |
| Change 2 |
|
+ 14 |
| After |
1x6 =
6 u |
|
Comparing the number
of packs in the end |
6 u |
1 u |
The number of packs of 2 in the end is repeated. Make the number of packs of 2 in the end the same. LCM of 1 and 6 is 6.
The number of packs of 2 at first is repeated. Make the number of packs of 2 at first the same. LCM of 12 and 6 is 12.
Number of pens
left unsold |
Packs of 2
|
Packs of 5
|
Total
|
| Number |
6 u |
1 u |
|
| Value |
2 |
5 |
|
| Total value |
12 u |
5 u |
17 u |
Total number of pens left unsold
= (6 u x 2) + (1 u x 5)
= 12 u + 5 u
= 17 u
17 u = 136
1 u = 136 ÷ 17 = 8
Number of packs of 5 sold
= (2 u - 1 u) + 14
= 1 u + 14
= 1 x 8 + 14
= 8 + 14
= 22
Answer(s): 22
