A bag contained white and green erasers. There were 60% more white erasers than green erasers. When 44 erasers were removed from the bag, the amount of white erasers decreased by 25% and the amount of green erasers decreased 70%. How many erasers were in the bag in the end?
| |
White erasers |
Green erasers |
Total erasers |
| Before |
8 u |
5 u |
13 u |
| Change |
- 2 u |
- 3.5 u |
- 5.5 u |
| After |
6 u |
1.5 u |
7.5 u |
100% + 60% = 160%
160% =
160100 =
85Number of white erasers that were removed from the bag
= 25% x 8 u
=
25100 x 8 u
= 2 u
Number of green erasers that were removed from the bag
= 70% x 5 u
=
70100 x 5 u
= 3.5 u
Total number of erasers that were removed from the bag
= 2 u + 3.5 u
= 5.5 u
5.5 u = 44
1 u = 44 ÷ 5.5 = 8
Number of erasers in the bag in the end
= 6 u + 1.5
= 7.5 u
= 7.5 x 8
= 60
Answer(s): 60
