A bag contained red and purple pens. There were 60% more red pens than purple pens. When 13 more pens were poured into the bag, the amount of red pens increased by 25% and the amount of purple pens increased 90%. How many pens were in the bag at first?
| |
Red pens |
Purple pens |
Total pens |
| Before |
8 u |
5 u |
13 u |
| Change |
+ 2 u |
+ 4.5 u |
+ 6.5 u |
| After |
10 u |
9.5 u |
19.5 u |
100% + 60% = 160%
160% =
160100 =
85Number of more red pens that were poured into the bag
= 25% x 8 u
=
25100 x 8 u
= 2 u
Number of more purple pens that were poured into the bag
= 90% x 5 u
=
90100 x 5 u
= 4.5 u
Total number of more pens that were poured into the bag
= 2 u + 4.5 u
= 6.5 u
6.5 u = 13
1 u = 13 ÷ 6.5 = 2
Number of pens in the bag at first
= 8 u + 5 u
= 13 u
= 13 x 2
= 26
Answer(s): 26
