A box contained pink and black coins. There were 60% more pink coins than black coins. When 22 coins were removed from the box, the amount of pink coins decreased by 25% and the amount of black coins decreased 70%. How many coins were in the box in the end?
| |
Pink coins |
Black coins |
Total coins |
| Before |
8 u |
5 u |
13 u |
| Change |
- 2 u |
- 3.5 u |
- 5.5 u |
| After |
6 u |
1.5 u |
7.5 u |
100% + 60% = 160%
160% =
160100 =
85Number of pink coins that were removed from the box
= 25% x 8 u
=
25100 x 8 u
= 2 u
Number of black coins that were removed from the box
= 70% x 5 u
=
70100 x 5 u
= 3.5 u
Total number of coins that were removed from the box
= 2 u + 3.5 u
= 5.5 u
5.5 u = 22
1 u = 22 ÷ 5.5 = 4
Number of coins in the box in the end
= 6 u + 1.5
= 7.5 u
= 7.5 x 4
= 30
Answer(s): 30
