Three types of sugar, L, M and N come in containers of 120 g, 240 g and 360 g respectively. Containers of L, M and N are mixed together in the ratio 2 : 3 : 5 to obtain 13.8 kg of an assortment of sugar.
- How many containers of L and M are used altogether?
- Find the difference between the combined weight of all the sugar in containers M and containers N as compared to the sugar in containers L. Express the weight in kilograms.
|
L |
M |
N |
Number |
2 u |
3 u |
5 u |
Value |
120 |
240 |
360 |
Total value |
240 u |
720 u |
1800 u |
(a)
Total mass of sugar
= 240 u + 720 u + 1800 u
= 2760 u
2760 u = 13800
1 u = 13800 ÷ 2760 = 5
Total number of containers of L and M used
= 2 u + 3 u
= 5 u
= 5 x 5
= 25
(b)
Combined weight of all the sugar in containers M and containers N
= 720 u + 1800 u
= 2520 u
Difference between the combined weight of all the sugar in containers M and containers N as compared to the sugar in containers L
= 2520 u - 240 u
= 2280 u
= 2280 x 5
= 11400 g
= 11.4 kg
Answer(s): (a) 25; (b) 11.4 kg