Three types of flour, M, N and P come in containers of 80 g, 200 g and 280 g respectively. Containers of M, N and P are mixed together in the ratio 2 : 4 : 5 to obtain 14.16 kg of an assortment of flour.
- How many containers of M and N are used altogether?
- Find the difference between the combined weight of all the flour in containers N and containers P as compared to the flour in containers M. Express the weight in kilograms.
|
M |
N |
P |
Number |
2 u |
4 u |
5 u |
Value |
80 |
200 |
280 |
Total value |
160 u |
800 u |
1400 u |
(a)
Total mass of flour
= 160 u + 800 u + 1400 u
= 2360 u
2360 u = 14160
1 u = 14160 ÷ 2360 = 6
Total number of containers of M and N used
= 2 u + 4 u
= 6 u
= 6 x 6
= 36
(b)
Combined weight of all the flour in containers N and containers P
= 800 u + 1400 u
= 2200 u
Difference between the combined weight of all the flour in containers N and containers P as compared to the flour in containers M
= 2200 u - 160 u
= 2040 u
= 2040 x 6
= 12240 g
= 12.24 kg
Answer(s): (a) 36; (b) 12.24 kg