Three types of chilli powder, S, T and U come in containers of 100 g, 150 g and 250 g respectively. Containers of S, T and U are mixed together in the ratio 3 : 4 : 6 to obtain 24 kg of an assortment of chilli powder.
- How many containers of S and T are used altogether?
- Find the difference between the combined weight of all the chilli powder in containers T and containers U as compared to the chilli powder in containers S. Express the weight in kilograms.
|
S |
T |
U |
Number |
3 u |
4 u |
6 u |
Value |
100 |
150 |
250 |
Total value |
300 u |
600 u |
1500 u |
(a)
Total mass of chilli powder
= 300 u + 600 u + 1500 u
= 2400 u
2400 u = 24000
1 u = 24000 ÷ 2400 = 10
Total number of containers of S and T used
= 3 u + 4 u
= 7 u
= 7 x 10
= 70
(b)
Combined weight of all the chilli powder in containers T and containers U
= 600 u + 1500 u
= 2100 u
Difference between the combined weight of all the chilli powder in containers T and containers U as compared to the chilli powder in containers S
= 2100 u - 300 u
= 1800 u
= 1800 x 10
= 18000 g
= 18 kg
Answer(s): (a) 70; (b) 18 kg