Three types of pepper, D, E and F come in containers of 160 g, 280 g and 400 g respectively. Containers of D, E and F are mixed together in the ratio 3 : 4 : 7 to obtain 30.8 kg of an assortment of pepper.
- How many containers of D and E are used altogether?
- Find the difference between the combined weight of all the pepper in containers E and containers F as compared to the pepper in containers D. Express the weight in kilograms.
|
D |
E |
F |
Number |
3 u |
4 u |
7 u |
Value |
160 |
280 |
400 |
Total value |
480 u |
1120 u |
2800 u |
(a)
Total mass of pepper
= 480 u + 1120 u + 2800 u
= 4400 u
4400 u = 30800
1 u = 30800 ÷ 4400 = 7
Total number of containers of D and E used
= 3 u + 4 u
= 7 u
= 7 x 7
= 49
(b)
Combined weight of all the pepper in containers E and containers F
= 1120 u + 2800 u
= 3920 u
Difference between the combined weight of all the pepper in containers E and containers F as compared to the pepper in containers D
= 3920 u - 480 u
= 3440 u
= 3440 x 7
= 24080 g
= 24.08 kg
Answer(s): (a) 49; (b) 24.08 kg