Three types of chicken powder, D, E and F come in containers of 100 g, 250 g and 400 g respectively. Containers of D, E and F are mixed together in the ratio 1 : 2 : 4 to obtain 24.2 kg of an assortment of chicken powder.
- How many containers of D and E are used altogether?
- Find the difference between the combined weight of all the chicken powder in containers E and containers F as compared to the chicken powder in containers D. Express the weight in kilograms.
|
D |
E |
F |
Number |
1 u |
2 u |
4 u |
Value |
100 |
250 |
400 |
Total value |
100 u |
500 u |
1600 u |
(a)
Total mass of chicken powder
= 100 u + 500 u + 1600 u
= 2200 u
2200 u = 24200
1 u = 24200 ÷ 2200 = 11
Total number of containers of D and E used
= 1 u + 2 u
= 3 u
= 3 x 11
= 33
(b)
Combined weight of all the chicken powder in containers E and containers F
= 500 u + 1600 u
= 2100 u
Difference between the combined weight of all the chicken powder in containers E and containers F as compared to the chicken powder in containers D
= 2100 u - 100 u
= 2000 u
= 2000 x 11
= 22000 g
= 22 kg
Answer(s): (a) 33; (b) 22 kg