Three types of sugar, D, E and F come in containers of 120 g, 180 g and 360 g respectively. Containers of D, E and F are mixed together in the ratio 3 : 5 : 8 to obtain 28.98 kg of an assortment of sugar.
- How many containers of D and E are used altogether?
- Find the difference between the combined weight of all the sugar in containers E and containers F as compared to the sugar in containers D. Express the weight in kilograms.
|
D |
E |
F |
Number |
3 u |
5 u |
8 u |
Value |
120 |
180 |
360 |
Total value |
360 u |
900 u |
2880 u |
(a)
Total mass of sugar
= 360 u + 900 u + 2880 u
= 4140 u
4140 u = 28980
1 u = 28980 ÷ 4140 = 7
Total number of containers of D and E used
= 3 u + 5 u
= 8 u
= 8 x 7
= 56
(b)
Combined weight of all the sugar in containers E and containers F
= 900 u + 2880 u
= 3780 u
Difference between the combined weight of all the sugar in containers E and containers F as compared to the sugar in containers D
= 3780 u - 360 u
= 3420 u
= 3420 x 7
= 23940 g
= 23.94 kg
Answer(s): (a) 56; (b) 23.94 kg