Three types of flour, D, E and F come in containers of 100 g, 200 g and 300 g respectively. Containers of D, E and F are mixed together in the ratio 3 : 6 : 8 to obtain 23.4 kg of an assortment of flour.
- How many containers of D and E are used altogether?
- Find the difference between the combined weight of all the flour in containers E and containers F as compared to the flour in containers D. Express the weight in kilograms.
|
D |
E |
F |
Number |
3 u |
6 u |
8 u |
Value |
100 |
200 |
300 |
Total value |
300 u |
1200 u |
2400 u |
(a)
Total mass of flour
= 300 u + 1200 u + 2400 u
= 3900 u
3900 u = 23400
1 u = 23400 ÷ 3900 = 6
Total number of containers of D and E used
= 3 u + 6 u
= 9 u
= 9 x 6
= 54
(b)
Combined weight of all the flour in containers E and containers F
= 1200 u + 2400 u
= 3600 u
Difference between the combined weight of all the flour in containers E and containers F as compared to the flour in containers D
= 3600 u - 300 u
= 3300 u
= 3300 x 6
= 19800 g
= 19.8 kg
Answer(s): (a) 54; (b) 19.8 kg