Three types of chicken powder, D, E and F come in containers of 200 g, 350 g and 400 g respectively. Containers of D, E and F are mixed together in the ratio 1 : 2 : 4 to obtain 12.5 kg of an assortment of chicken powder.
- How many containers of D and E are used altogether?
- Find the difference between the combined weight of all the chicken powder in containers E and containers F as compared to the chicken powder in containers D. Express the weight in kilograms.
|
D |
E |
F |
Number |
1 u |
2 u |
4 u |
Value |
200 |
350 |
400 |
Total value |
200 u |
700 u |
1600 u |
(a)
Total mass of chicken powder
= 200 u + 700 u + 1600 u
= 2500 u
2500 u = 12500
1 u = 12500 ÷ 2500 = 5
Total number of containers of D and E used
= 1 u + 2 u
= 3 u
= 3 x 5
= 15
(b)
Combined weight of all the chicken powder in containers E and containers F
= 700 u + 1600 u
= 2300 u
Difference between the combined weight of all the chicken powder in containers E and containers F as compared to the chicken powder in containers D
= 2300 u - 200 u
= 2100 u
= 2100 x 5
= 10500 g
= 10.5 kg
Answer(s): (a) 15; (b) 10.5 kg