Three types of flour, L, M and N come in containers of 60 g, 150 g and 240 g respectively. Containers of L, M and N are mixed together in the ratio 3 : 6 : 7 to obtain 30.36 kg of an assortment of flour.
- How many containers of L and M are used altogether?
- Find the difference between the combined weight of all the flour in containers M and containers N as compared to the flour in containers L. Express the weight in kilograms.
|
L |
M |
N |
Number |
3 u |
6 u |
7 u |
Value |
60 |
150 |
240 |
Total value |
180 u |
900 u |
1680 u |
(a)
Total mass of flour
= 180 u + 900 u + 1680 u
= 2760 u
2760 u = 30360
1 u = 30360 ÷ 2760 = 11
Total number of containers of L and M used
= 3 u + 6 u
= 9 u
= 9 x 11
= 99
(b)
Combined weight of all the flour in containers M and containers N
= 900 u + 1680 u
= 2580 u
Difference between the combined weight of all the flour in containers M and containers N as compared to the flour in containers L
= 2580 u - 180 u
= 2400 u
= 2400 x 11
= 26400 g
= 26.4 kg
Answer(s): (a) 99; (b) 26.4 kg