PSLEThere were a total of 102 tables and chairs in a basketball court. There were 2 times as many chairs as tables. After 28 chairs and some tables were thrown away, there were 4 times as many chairs as tables left. How many tables were thrown away from the basketball court?
|
Tables |
Chairs |
Total |
Before |
1 u |
2 u |
102 |
Change |
- ? |
- 28 |
|
After |
1 p |
4 p |
|
Number of tables and chairs at first
= 2 u + 1 u
= 102
3 u = 102
1 u = 102 ÷ 3 = 34
Number of chairs at first
= 2 u
= 2 x 34
= 68
Number of chairs left
= 68 - 28
= 40
4 p = 40
1 p = 40 ÷ 4 = 10
Number of tables thrown away from the basketball court
= 34 - 10
= 24
Answer(s): 24