PSLEA stallholder had an equal number of pears, chikoos and peaches at first. After 57 peaches, some pears and chikoos were sold, there were 117 fruits left. There were 4 times as many pears as chikoos left. The number of peaches left was 27 fewer than the number of pears left. How many chikoos were sold?
|
Pears |
Chikoos |
Peaches |
Total |
Before |
1 |
1 |
1 |
|
Change |
- ? |
- ? |
- 57 |
|
After |
4 u |
1 u |
4 u - 27 |
117 |
Total number of fruits in the end
= 4 u + 1 u + 4 u - 27
= 9 u - 27
9 u - 27 = 117
9 u = 117 + 27
9 u = 144
1 u = 144 ÷ 9 = 16
Number of peaches at first
= 4 u - 27 + 57
= 4 x 16 + 30
= 94
The number of peaches and chikoos at first is the same.
Number of chikoos sold
= 94 - 16
= 78
Answer(s): 78