PSLEA stallholder had the same number of kiwis, peaches and pears at first. After 56 pears, some kiwis and peaches were sold, there were 119 fruits left. There were 2 times as many kiwis as peaches left. The number of pears left was 21 less than the number of kiwis left. How many peaches were sold?
|
Kiwis |
Peaches |
Pears |
Total |
Before |
1 |
1 |
1 |
|
Change |
- ? |
- ? |
- 56 |
|
After |
2 u |
1 u |
2 u - 21 |
119 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 21
= 5 u - 21
5 u - 21 = 119
5 u = 119 + 21
5 u = 140
1 u = 140 ÷ 5 = 28
Number of pears at first
= 2 u - 21 + 56
= 2 x 28 + 35
= 91
The number of pears and peaches at first is the same.
Number of peaches sold
= 91 - 28
= 63
Answer(s): 63