A stallholder had the same number of chikoos, persimmons and pomegranates at first. After 61 pomegranates, some chikoos and persimmons were set aside, there were 122 fruits left. There were four times as many chikoos as persimmons left. The number of pomegranates left was 13 fewer than the number of chikoos. How many persimmons were set aside?
| |
Chikoos |
Persimmons |
Pomegranates |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 61 |
|
| After |
4 u |
1 u |
4 u - 13 |
122 |
Total number of fruits in the end
= 4 u + 1 u + 4 u - 13
= 9 u - 13
9 u - 13 = 122
9 u = 122 + 13
9 u = 135
1 u = 135 ÷ 9 = 15
Number of pomegranates at first
= 4 u - 13 + 61
= 4 x 15 - 13 + 61
= 60 - 13 + 61
= 108
The number of persimmons and pomegranates at first was the same.
Number of persimmons set aside
= 108 - 1 u
= 108 - 15
= 93
Answer(s): 93
