A grocer had the same number of mangoes, chikoos and pears at first. After 49 pears, some mangoes and chikoos were removed, there were 182 fruits left. There were twice as many mangoes as chikoos left. The number of pears left was 28 fewer than the number of mangoes. How many chikoos were removed?
| |
Mangoes |
Chikoos |
Pears |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 49 |
|
| After |
2 u |
1 u |
2 u - 28 |
182 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 28
= 5 u - 28
5 u - 28 = 182
5 u = 182 + 28
5 u = 210
1 u = 210 ÷ 5 = 42
Number of pears at first
= 2 u - 28 + 49
= 2 x 42 - 28 + 49
= 84 - 28 + 49
= 105
The number of chikoos and pears at first was the same.
Number of chikoos removed
= 105 - 1 u
= 105 - 42
= 63
Answer(s): 63
