A store owner had the same number of starfruits, guavas and dragonfruits at first. After 51 dragonfruits, some starfruits and guavas were set aside, there were 108 fruits left. There were twice as many starfruits as guavas left. The number of dragonfruits left was 17 fewer than the number of starfruits. How many guavas were set aside?
| |
Starfruits |
Guavas |
Dragonfruits |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 51 |
|
| After |
2 u |
1 u |
2 u - 17 |
108 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 17
= 5 u - 17
5 u - 17 = 108
5 u = 108 + 17
5 u = 125
1 u = 125 ÷ 5 = 25
Number of dragonfruits at first
= 2 u - 17 + 51
= 2 x 25 - 17 + 51
= 50 - 17 + 51
= 84
The number of guavas and dragonfruits at first was the same.
Number of guavas set aside
= 84 - 1 u
= 84 - 25
= 59
Answer(s): 59
