A grocer had the same number of chikoos, kiwis and pears at first. After 130 pears, some chikoos and kiwis were removed, there were 102 fruits left. There were twice as many chikoos as kiwis left. The number of pears left was 13 less than the number of chikoos. How many kiwis were removed?
| |
Chikoos |
Kiwis |
Pears |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 130 |
|
| After |
2 u |
1 u |
2 u - 13 |
102 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 13
= 5 u - 13
5 u - 13 = 102
5 u = 102 + 13
5 u = 115
1 u = 115 ÷ 5 = 23
Number of pears at first
= 2 u - 13 + 130
= 2 x 23 - 13 + 130
= 46 - 13 + 130
= 163
The number of kiwis and pears at first was the same.
Number of kiwis removed
= 163 - 1 u
= 163 - 23
= 140
Answer(s): 140
