A stallholder had the same number of pears, mangoes and kiwis at first. After 83 kiwis, some pears and mangoes were thrown away, there were 115 fruits left. There were five times as many pears as mangoes left. The number of kiwis left was 39 fewer than the number of pears. How many mangoes were thrown away?
| |
Pears |
Mangoes |
Kiwis |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 83 |
|
| After |
5 u |
1 u |
5 u - 39 |
115 |
Total number of fruits in the end
= 5 u + 1 u + 5 u - 39
= 11 u - 39
11 u - 39 = 115
11 u = 115 + 39
11 u = 154
1 u = 154 ÷ 11 = 14
Number of kiwis at first
= 5 u - 39 + 83
= 5 x 14 - 39 + 83
= 70 - 39 + 83
= 114
The number of mangoes and kiwis at first was the same.
Number of mangoes thrown away
= 114 - 1 u
= 114 - 14
= 100
Answer(s): 100
