A store owner had the same number of chikoos, mangoes and guavas at first. After 70 guavas, some chikoos and mangoes were removed, there were 190 fruits left. There were thrice as many chikoos as mangoes left. The number of guavas left was 13 fewer than the number of chikoos. How many mangoes were removed?
| |
Chikoos |
Mangoes |
Guavas |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 70 |
|
| After |
3 u |
1 u |
3 u - 13 |
190 |
Total number of fruits in the end
= 3 u + 1 u + 3 u - 13
= 7 u - 13
7 u - 13 = 190
7 u = 190 + 13
7 u = 203
1 u = 203 ÷ 7 = 29
Number of guavas at first
= 3 u - 13 + 70
= 3 x 29 - 13 + 70
= 87 - 13 + 70
= 144
The number of mangoes and guavas at first was the same.
Number of mangoes removed
= 144 - 1 u
= 144 - 29
= 115
Answer(s): 115
