A fruit seller had the same number of peaches, dragonfruits and persimmons at first. After 114 persimmons, some peaches and dragonfruits were removed, there were 98 fruits left. There were thrice as many peaches as dragonfruits left. The number of persimmons left was 28 less than the number of peaches. How many dragonfruits were removed?
| |
Peaches |
Dragonfruits |
Persimmons |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 114 |
|
| After |
3 u |
1 u |
3 u - 28 |
98 |
Total number of fruits in the end
= 3 u + 1 u + 3 u - 28
= 7 u - 28
7 u - 28 = 98
7 u = 98 + 28
7 u = 126
1 u = 126 ÷ 7 = 18
Number of persimmons at first
= 3 u - 28 + 114
= 3 x 18 - 28 + 114
= 54 - 28 + 114
= 140
The number of dragonfruits and persimmons at first was the same.
Number of dragonfruits removed
= 140 - 1 u
= 140 - 18
= 122
Answer(s): 122
