A store owner had the same number of peaches, chikoos and mangoes at first. After 148 mangoes, some peaches and chikoos were thrown away, there were 130 fruits left. There were twice as many peaches as chikoos left. The number of mangoes left was 10 less than the number of peaches. How many chikoos were thrown away?
| |
Peaches |
Chikoos |
Mangoes |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 148 |
|
| After |
2 u |
1 u |
2 u - 10 |
130 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 10
= 5 u - 10
5 u - 10 = 130
5 u = 130 + 10
5 u = 140
1 u = 140 ÷ 5 = 28
Number of mangoes at first
= 2 u - 10 + 148
= 2 x 28 - 10 + 148
= 56 - 10 + 148
= 194
The number of chikoos and mangoes at first was the same.
Number of chikoos thrown away
= 194 - 1 u
= 194 - 28
= 166
Answer(s): 166
