A stallholder had the same number of guavas, persimmons and kiwis at first. After 73 kiwis, some guavas and persimmons were sold, there were 197 fruits left. There were five times as many guavas as persimmons left. The number of kiwis left was 34 fewer than the number of guavas. How many persimmons were sold?
| |
Guavas |
Persimmons |
Kiwis |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 73 |
|
| After |
5 u |
1 u |
5 u - 34 |
197 |
Total number of fruits in the end
= 5 u + 1 u + 5 u - 34
= 11 u - 34
11 u - 34 = 197
11 u = 197 + 34
11 u = 231
1 u = 231 ÷ 11 = 21
Number of kiwis at first
= 5 u - 34 + 73
= 5 x 21 - 34 + 73
= 105 - 34 + 73
= 144
The number of persimmons and kiwis at first was the same.
Number of persimmons sold
= 144 - 1 u
= 144 - 21
= 123
Answer(s): 123
