A grocer had the same number of pears, passion fruits and chikoos at first. After 75 chikoos, some pears and passion fruits were removed, there were 106 fruits left. There were thrice as many pears as passion fruits left. The number of chikoos left was 20 less than the number of pears. How many passion fruits were removed?
| |
Pears |
Passion Fruits |
Chikoos |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 75 |
|
| After |
3 u |
1 u |
3 u - 20 |
106 |
Total number of fruits in the end
= 3 u + 1 u + 3 u - 20
= 7 u - 20
7 u - 20 = 106
7 u = 106 + 20
7 u = 126
1 u = 126 ÷ 7 = 18
Number of chikoos at first
= 3 u - 20 + 75
= 3 x 18 - 20 + 75
= 54 - 20 + 75
= 109
The number of passion fruits and chikoos at first was the same.
Number of passion fruits removed
= 109 - 1 u
= 109 - 18
= 91
Answer(s): 91
