A stallholder had the same number of chikoos, guavas and mangoes at first. After 56 mangoes, some chikoos and guavas were taken out, there were 129 fruits left. There were thrice as many chikoos as guavas left. The number of mangoes left was 39 less than the number of chikoos. How many guavas were taken out?
| |
Chikoos |
Guavas |
Mangoes |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 56 |
|
| After |
3 u |
1 u |
3 u - 39 |
129 |
Total number of fruits in the end
= 3 u + 1 u + 3 u - 39
= 7 u - 39
7 u - 39 = 129
7 u = 129 + 39
7 u = 168
1 u = 168 ÷ 7 = 24
Number of mangoes at first
= 3 u - 39 + 56
= 3 x 24 - 39 + 56
= 72 - 39 + 56
= 89
The number of guavas and mangoes at first was the same.
Number of guavas taken out
= 89 - 1 u
= 89 - 24
= 65
Answer(s): 65
