A grocer had the same number of persimmons, peaches and lemons at first. After 67 lemons, some persimmons and peaches were taken out, there were 187 fruits left. There were twice as many persimmons as peaches left. The number of lemons left was 28 less than the number of persimmons. How many peaches were taken out?
|
Persimmons |
Peaches |
Lemons |
Total |
Before |
1 |
1 |
1 |
|
Change |
- ? |
- ? |
- 67 |
|
After |
2 u |
1 u |
2 u - 28 |
187 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 28
= 5 u - 28
5 u - 28 = 187
5 u = 187 + 28
5 u = 215
1 u = 215 ÷ 5 = 43
Number of lemons at first
= 2 u - 28 + 67
= 2 x 43 - 28 + 67
= 86 - 28 + 67
= 125
The number of peaches and lemons at first was the same.
Number of peaches taken out
= 125 - 1 u
= 125 - 43
= 82
Answer(s): 82