A grocer had the same number of grapefruits, chikoos and lemons at first. After 118 lemons, some grapefruits and chikoos were set aside, there were 91 fruits left. There were five times as many grapefruits as chikoos left. The number of lemons left was 30 fewer than the number of grapefruits. How many chikoos were set aside?
| |
Grapefruits |
Chikoos |
Lemons |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 118 |
|
| After |
5 u |
1 u |
5 u - 30 |
91 |
Total number of fruits in the end
= 5 u + 1 u + 5 u - 30
= 11 u - 30
11 u - 30 = 91
11 u = 91 + 30
11 u = 121
1 u = 121 ÷ 11 = 11
Number of lemons at first
= 5 u - 30 + 118
= 5 x 11 - 30 + 118
= 55 - 30 + 118
= 143
The number of chikoos and lemons at first was the same.
Number of chikoos set aside
= 143 - 1 u
= 143 - 11
= 132
Answer(s): 132
