A fruit seller had the same number of peaches, guavas and pomegranates at first. After 126 pomegranates, some peaches and guavas were sold, there were 96 fruits left. There were four times as many peaches as guavas left. The number of pomegranates left was 21 less than the number of peaches. How many guavas were sold?
| |
Peaches |
Guavas |
Pomegranates |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 126 |
|
| After |
4 u |
1 u |
4 u - 21 |
96 |
Total number of fruits in the end
= 4 u + 1 u + 4 u - 21
= 9 u - 21
9 u - 21 = 96
9 u = 96 + 21
9 u = 117
1 u = 117 ÷ 9 = 13
Number of pomegranates at first
= 4 u - 21 + 126
= 4 x 13 - 21 + 126
= 52 - 21 + 126
= 157
The number of guavas and pomegranates at first was the same.
Number of guavas sold
= 157 - 1 u
= 157 - 13
= 144
Answer(s): 144
