A store owner had the same number of grapefruits, guavas and mangoes at first. After 138 mangoes, some grapefruits and guavas were sold, there were 158 fruits left. There were thrice as many grapefruits as guavas left. The number of mangoes left was 10 fewer than the number of grapefruits. How many guavas were sold?
| |
Grapefruits |
Guavas |
Mangoes |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 138 |
|
| After |
3 u |
1 u |
3 u - 10 |
158 |
Total number of fruits in the end
= 3 u + 1 u + 3 u - 10
= 7 u - 10
7 u - 10 = 158
7 u = 158 + 10
7 u = 168
1 u = 168 ÷ 7 = 24
Number of mangoes at first
= 3 u - 10 + 138
= 3 x 24 - 10 + 138
= 72 - 10 + 138
= 200
The number of guavas and mangoes at first was the same.
Number of guavas sold
= 200 - 1 u
= 200 - 24
= 176
Answer(s): 176
