A fruit seller had the same number of grapefruits, persimmons and kiwis at first. After 59 kiwis, some grapefruits and persimmons were given away, there were 172 fruits left. There were twice as many grapefruits as persimmons left. The number of kiwis left was 38 fewer than the number of grapefruits. How many persimmons were given away?
|
Grapefruits |
Persimmons |
Kiwis |
Total |
Before |
1 |
1 |
1 |
|
Change |
- ? |
- ? |
- 59 |
|
After |
2 u |
1 u |
2 u - 38 |
172 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 38
= 5 u - 38
5 u - 38 = 172
5 u = 172 + 38
5 u = 210
1 u = 210 ÷ 5 = 42
Number of kiwis at first
= 2 u - 38 + 59
= 2 x 42 - 38 + 59
= 84 - 38 + 59
= 105
The number of persimmons and kiwis at first was the same.
Number of persimmons given away
= 105 - 1 u
= 105 - 42
= 63
Answer(s): 63