A store owner had the same number of kiwis, passion fruits and peaches at first. After 64 peaches, some kiwis and passion fruits were set aside, there were 105 fruits left. There were four times as many kiwis as passion fruits left. The number of peaches left was 30 less than the number of kiwis. How many passion fruits were set aside?
| |
Kiwis |
Passion Fruits |
Peaches |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 64 |
|
| After |
4 u |
1 u |
4 u - 30 |
105 |
Total number of fruits in the end
= 4 u + 1 u + 4 u - 30
= 9 u - 30
9 u - 30 = 105
9 u = 105 + 30
9 u = 135
1 u = 135 ÷ 9 = 15
Number of peaches at first
= 4 u - 30 + 64
= 4 x 15 - 30 + 64
= 60 - 30 + 64
= 94
The number of passion fruits and peaches at first was the same.
Number of passion fruits set aside
= 94 - 1 u
= 94 - 15
= 79
Answer(s): 79
