A store owner had the same number of peaches, pears and chikoos at first. After 118 chikoos, some peaches and pears were used, there were 146 fruits left. There were thrice as many peaches as pears left. The number of chikoos left was 22 fewer than the number of peaches. How many pears were used?
| |
Peaches |
Pears |
Chikoos |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 118 |
|
| After |
3 u |
1 u |
3 u - 22 |
146 |
Total number of fruits in the end
= 3 u + 1 u + 3 u - 22
= 7 u - 22
7 u - 22 = 146
7 u = 146 + 22
7 u = 168
1 u = 168 ÷ 7 = 24
Number of chikoos at first
= 3 u - 22 + 118
= 3 x 24 - 22 + 118
= 72 - 22 + 118
= 168
The number of pears and chikoos at first was the same.
Number of pears used
= 168 - 1 u
= 168 - 24
= 144
Answer(s): 144
