A stallholder had the same number of starfruits, peaches and mangosteens at first. After 122 mangosteens, some starfruits and peaches were set aside, there were 95 fruits left. There were twice as many starfruits as peaches left. The number of mangosteens left was 10 less than the number of starfruits. How many peaches were set aside?
| |
Starfruits |
Peaches |
Mangosteens |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 122 |
|
| After |
2 u |
1 u |
2 u - 10 |
95 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 10
= 5 u - 10
5 u - 10 = 95
5 u = 95 + 10
5 u = 105
1 u = 105 ÷ 5 = 21
Number of mangosteens at first
= 2 u - 10 + 122
= 2 x 21 - 10 + 122
= 42 - 10 + 122
= 154
The number of peaches and mangosteens at first was the same.
Number of peaches set aside
= 154 - 1 u
= 154 - 21
= 133
Answer(s): 133
